However, late 19th century experiments with Bohr's condition, that the angular momentum is an integer multiple of According to de Broglie hypothesis, matter particles such as the electron behaves as waves. Is "frequency of an electron" an experimental quantity? Detailed answers to any questions you might have
The Bohr model is a relatively primitive model of the Also, as the electron spirals inward, the emission would rapidly increase in frequency as the orbit got smaller and faster. So, de Broglie wavelength of electron is: If an electron in an atom is moving on an orbit with period In quantum mechanics, this emission must be in quanta of light, of frequencies consisting of integer multiples of 1/Bohr considered circular orbits.
The However, this is not to say that the Bohr-Sommerfeld model was without its successes. Heavier atoms have more protons in the nucleus, and more electrons to cancel the charge. If it refers to the rotation of electron around a nucleus, then which phenomenon is considered for a free electron i.e. The third orbital contains eight again, except that in the more correct Sommerfeld treatment (reproduced in modern quantum mechanics) there are extra "d" electrons. Physics Stack Exchange works best with JavaScript enabled
Bohr's idea was that each discrete orbit could only hold a certain number of electrons. If one kept track of the constants, the spacing would be An electron in the lowest energy level of hydrogen (The combination of natural constants in the energy formula is called the Rydberg energy (This expression is clarified by interpreting it in combinations that form more Since this derivation is with the assumption that the nucleus is orbited by one electron, we can generalize this result by letting the nucleus have a charge The actual energy levels cannot be solved analytically for more than one electron (see However, these numbers are very nearly the same, due to the much larger mass of the proton, about 1836.1 times the mass of the electron, so that the reduced mass in the system is the mass of the electron multiplied by the constant 1836.1/(1+1836.1) = 0.99946. By using our site, you acknowledge that you have read and understand our Physics Stack Exchange is a question and answer site for active researchers, academics and students of physics. My teacher told me how to calculate the frequency of an electron. This gives the atom a This model is even more approximate than the model of hydrogen, because it treats the electrons in each shell as non-interacting.